![]() ![]() ![]() Perpendicular Bisector of AchordĪ line that passes through a chord at a right angle ( the perpendicular bisector), passes through the centre of the circle. That’s why this theorem works! Think straight line = angles in a triangle. Equally if you know to angles in a triangle the missing angle is 180- the two you know. Therefore if you know two angles on a straight line the missing angle must be 180- the two you know added together. The key to this theorem is remembering that there are 180 degrees on a straight line and 180 degrees in a triangle. From the segment to the circumference to the other segment, it creates an identical angle! Alternate Segment Theorem Think about how you can trace the lines without removing your pen from the page. These angles are created at same points on a segment. Where a tangent meets a radius it creates an angles of 90 degrees. This is not a cyclic quadrilateral as the points don’t all touch the circumference of the circle. To be a cyclic quadrilateral all points of the quadrilateral must touch the circumference. Opposite angles in a cyclic quadrilateral ( a quadrilateral in a circle) will always add to 180 degrees. The angle at the centre of a circle is always _double that of the angle at the circumference if both angles are ‘_subtended’ (created) from the same two points on a chord.Ī triangle within a circle with the diameter as base will always have a right angle at the circumference. So lets see, we could divide the numerator and the denominator by six. So lets see if we can simplify this a little bit. Expressing One Quality as a Fraction of Another So this arc length is going to be 135/360 of the entire circumference, so times six pi, six pi inches.Experimental Probability or Relative Frequency.Constructing, Describing and Identifying Shapes In this unit of work we are going to look at circle theorems and their application.Identifying Roots and Turning Points of Quadratic Functions.Calculating and Estimating Gradients of Graphs.Using Algebra to Find Real Life Solutions. ![]()
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